// 解答2.1 size2.c
// 最大値と最小値を求める(高速)
#include <stdio.h>
#include <stdlib.h>
#include <inttypes.h>

void long_int_minmax() {
    int32_t x,old_x;

    //最小値
    x = old_x = -1;
    while  (old_x > (x<<=1) ) {
       old_x = x;
    }
    printf("min=%" PRId32 ", ", old_x);

    //最大値
    x = old_x = 1;
    while (old_x < (x<<=1) ) {
       old_x = x;
    }
    printf("max=%" PRId32 "\n", x-1);
}

void long_int_minmax_fast() {
    int b = sizeof(long int);
    int d = 1<<(b*8-1);
    printf("min=%d, ", -d);
    printf("max=%d\n", d-1);
}

void print_size() {
    printf("sizeof(char)=%d\n", sizeof(char));
    printf("sizeof(short int)=%d\n", sizeof(short int));
    printf("sizeof(int)=%d\n", sizeof(int));
    printf("sizeof(long int)=%d\n", sizeof(long int));
    printf("sizeof(long long int)=%d\n", sizeof(long long int));
    printf("sizeof(pointer)=%d\n", sizeof(void*));
}

int main() {
    long_int_minmax();
    long_int_minmax_fast();
    print_size();
}